tag:blogger.com,1999:blog-306125072024-03-21T18:23:02.600-07:00Engineering SchoolThat Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.comBlogger16125tag:blogger.com,1999:blog-30612507.post-44364796839791848772013-08-20T14:06:00.003-07:002013-08-20T14:08:36.864-07:00Fracking In New YorkIt is up to Governor Cuomo to decide if <a class="zem_slink" href="http://en.wikipedia.org/wiki/New_York" rel="wikipedia" target="_blank" title="New York">New York State</a> will start drilling for natural gas using fracking. Officially known as <a class="zem_slink" href="http://en.wikipedia.org/wiki/Hydraulic_fracturing" rel="wikipedia" target="_blank" title="Hydraulic fracturing">hydraulic fracturing</a> this is method takes more natural gas out of shale formations deep underground. There are a few ways to take take <a class="zem_slink" href="http://en.wikipedia.org/wiki/Shale_gas" rel="wikipedia" target="_blank" title="Shale gas">shale gas</a> but this one is the most profitable.<br />
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Let me show a simplified graphic that shows what fracking basically does.<br />
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgezojQ0qsKt4P8bbHCLseAgCE2GCyHPng6_4X2aaX3PAxfATIKpzEk94ZmQnh3S1U0hWVPng7vAXqIvitbrm7mAvNdRiU8Z-ACtDoT4Pe4In6PxvZiE_lvR5YvTx801g4_adyhlA/s1600/shale-gas-extraction.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="400" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgezojQ0qsKt4P8bbHCLseAgCE2GCyHPng6_4X2aaX3PAxfATIKpzEk94ZmQnh3S1U0hWVPng7vAXqIvitbrm7mAvNdRiU8Z-ACtDoT4Pe4In6PxvZiE_lvR5YvTx801g4_adyhlA/s400/shale-gas-extraction.jpg" width="283" /></a></div>
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A hole is drilled into the ground and small explosives are used to get through the ancient shalebed of limestone that traps oil and gas. Most of the east coast of America has this formation underneath with 1-11% of gas-potential in New York State. Once the hole is made a casing, that should last for 50+ years, is made of layered cement that will act as a pipe. A mixture of water, over 750 chemicals, and an aggregate like sand is forced down the hole. This cracks the shale and releases the gas. Extensions to the original holes are made to control the pressure. When negative pressure is achieved a certain percentage of gas and fracking fluid is pushed through the pipe to the surface.<br />
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Whew and that is the simple explanation.<br />
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Here is the complex explanation and a list of what is left out:<br />
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh0mb1o8B5V0_R49ChMQqAD__L80sk40B3yqx9j_VHd7nXFyGvTGSBh44Rdf9XiNKl-Hzn_zriJKb8zHAh5dOHNpfUpaCCOLhHqHvm3Tr8ZDsnYX_oSiAZg2h4AuJUHZ4wYYJGixA/s1600/shale-gas.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="400" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh0mb1o8B5V0_R49ChMQqAD__L80sk40B3yqx9j_VHd7nXFyGvTGSBh44Rdf9XiNKl-Hzn_zriJKb8zHAh5dOHNpfUpaCCOLhHqHvm3Tr8ZDsnYX_oSiAZg2h4AuJUHZ4wYYJGixA/s400/shale-gas.jpg" width="341" /></a></div>
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<ul>
<li>Tens of thousands of gallons of fresh water is needed for each well.</li>
<li>Once the water is combined with the chemical slurry it cannot be uncombined. </li>
<li>Water, waste, and parts must be delivered via diesel trucks equally millions of trips per year. </li>
<li>Reservoir pits of fracking fluids are needed to hold the fluid until they are shipped of to be buried since it is not recyclable. </li>
<li>The cement casing are triple layered and have a 5% failure rate after 2 years and 40% failure rate after 25 years.</li>
<li>Fracking has been around in the U.S. since the 1970s and the recent boom started in 2008.</li>
<li>For residential prices natural gas was lowest per thousand cubic feet in 1981 around $4/ft<sup>3</sup> per and highest in 2008 at $16/ft<sup>3</sup>, currently in 2013 we are around $10/ft<sup>3</sup> .</li>
<li>The investment in fracking technology drove the prices high in 2008.</li>
<li>We have not seen lower prices since the September 11, 2001 attacks despite the massive drilling across the country.</li>
<li>These gas deposits are temporary and typical last 2-5 years. </li>
<li>New York estimates 10,000 to 100,000 wells can be drilled.</li>
</ul>
<a class="zem_slink" href="http://www.nypirg.org/" rel="homepage" target="_blank" title="New York Public Interest Research Group">NYPIRG</a> has been the most vocal group in New York since the watershed in the area is purest and cleanest in America and it reaches millions of people. This summer they have been warning residents of the possible dangers as well as soliciting memberships. Other environmental groups have been heavy handed and exaggerating claims but NYPIRG does seem to want New Yorkers to remain safe especially if gas prices wil not drop.<br />
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Engineering groups, gas companies, and tech businesses have been for fracking since failure rate is low and in New York more monitors will be used. Also the potential of jobs and lower gas bill, even if temporary is a great thing. <br />
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The New Yorkers have really been split. Many people are against the chemicals being used and the lack of waste water treatment plans. Still some just need a financial break and have confidence that if breaks do occur they will be dealt with in a timely manner. Of course 99% of the people do not want a gas well near them which speaks volumes.<br />
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Governor Cuomo of Mt. Kisco has remained silent on this issue and his past record has shown close ties to the gas oil industry. I expect despite NYPIRG's efforts that he will not decide anything until mid-2014. Personally I am against fracking but not drilling. I know there are alternatives to hydraulic fracturing and forcing the gas industry to use it will help all New Yorkers. I would enjoy working for the gas company if this can done safely, yes I have applied for them in the past as well as for the groups opposing them. Science should halp both sides come to a rational solution.<br />
<br />Manhttp://www.blogger.com/profile/02349516488425977793noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-49846765631978631042012-04-27T14:00:00.000-07:002012-04-27T14:00:17.220-07:00Space Shuttle NYCIt is cool.<br />
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgTQDzE0O6zIrZSSvwCjSbLo_mwLR4wCkzlvfya1LquneU3WpF0D9cCx5VvxoR5snEEXCLPJDtQqOSuQR80jWEJ5xrqWkjRRkBzOpMEK1SB8A4ZTF6EI0FS_jrFYLsLqwro4AZ5qg/s1600/IMG_9850b.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="77" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgTQDzE0O6zIrZSSvwCjSbLo_mwLR4wCkzlvfya1LquneU3WpF0D9cCx5VvxoR5snEEXCLPJDtQqOSuQR80jWEJ5xrqWkjRRkBzOpMEK1SB8A4ZTF6EI0FS_jrFYLsLqwro4AZ5qg/s400/IMG_9850b.jpg" width="400" /></a></div>
<br />That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com1tag:blogger.com,1999:blog-30612507.post-6178595754370589072009-06-30T12:41:00.000-07:002009-06-30T12:57:58.185-07:00Lightning and MammatusRecent NYC weather has us approaching records rainfall, which I enjoy.<br /><br />Plus it gave me a chance to take video of lightning and other weather phenomena.<br /><br /><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh9Em7mpG7M457i-AHbR9XY0Ws4J5nXBFpuldo_U_q9bnM4ztQ2lr3XtE7BwoanP-Q82LJnQPD14ZBs9W2SvPBa0Ttm1ygRxKRCT0ac6TMNYaowWwIl9SDGskV74SDYMiU4c8ltQQ/s1600-h/lightningf.jpg"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 400px; height: 479px;" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh9Em7mpG7M457i-AHbR9XY0Ws4J5nXBFpuldo_U_q9bnM4ztQ2lr3XtE7BwoanP-Q82LJnQPD14ZBs9W2SvPBa0Ttm1ygRxKRCT0ac6TMNYaowWwIl9SDGskV74SDYMiU4c8ltQQ/s400/lightningf.jpg" alt="" id="BLOGGER_PHOTO_ID_5353208606217706338" border="0" /></a>A great series of a lighting strike. Series goes from cloud lightning forming with a leader and secondary higher path, the initial strike, the height of brilliance.<br /><br /><br /><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhNuHAlodzxVlNxOuXjmC7SYgI10uEY9uR-Im62sjTJAlospWoxhyphenhyphen1-v2aNl2WZBjjBDgTfAZhCng9HnzCPt5D3wP5OSXGcJf8_0de5zhPhNLNLksqd4iwzv7YOf-kWxYomkKYJMA/s1600-h/purple.jpg"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 400px; height: 328px;" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhNuHAlodzxVlNxOuXjmC7SYgI10uEY9uR-Im62sjTJAlospWoxhyphenhyphen1-v2aNl2WZBjjBDgTfAZhCng9HnzCPt5D3wP5OSXGcJf8_0de5zhPhNLNLksqd4iwzv7YOf-kWxYomkKYJMA/s400/purple.jpg" alt="" id="BLOGGER_PHOTO_ID_5353208605312333490" border="0" /></a>After the strike in less then a second my camera turned purple. I assume this was from the electrical discharge.<br /><br /><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiimkkx6hdFr4Btp0vrOA47WmaS_oXqnOxpsWxZUm-BCLdF1ZFu2ovrWoiDdw2Jnhxca7cvgW81PpQwzrJTJwVVCgu-iCc0mK7JHVLY5X7L1f84QFDbKqG8zcZ89M9a234FfI1UFw/s1600-h/IMG_0439+%28Large%29.JPG"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 400px; height: 300px;" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiimkkx6hdFr4Btp0vrOA47WmaS_oXqnOxpsWxZUm-BCLdF1ZFu2ovrWoiDdw2Jnhxca7cvgW81PpQwzrJTJwVVCgu-iCc0mK7JHVLY5X7L1f84QFDbKqG8zcZ89M9a234FfI1UFw/s400/IMG_0439+%28Large%29.JPG" alt="" id="BLOGGER_PHOTO_ID_5353208603160712562" border="0" /></a>Then after the mini-storm a small group of mammatus clouds appeared at sunset.<br /><br /><div style="text-align: center;"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiNKa9ar1fmv05Z5yLG4vpx1U7JxqEztC0TJDiZcBMBfKBmdwfJa5_B9m7I7cgkwzEgYy_V9k53HsPs8tGVfzVMOpGINCc6l65o1ofeGwqQzIiXCMZb0cRKQctHNL4ceRZSsUUERA/s1600-h/IMG_0449+%28Large%29.JPG"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 400px; height: 300px;" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiNKa9ar1fmv05Z5yLG4vpx1U7JxqEztC0TJDiZcBMBfKBmdwfJa5_B9m7I7cgkwzEgYy_V9k53HsPs8tGVfzVMOpGINCc6l65o1ofeGwqQzIiXCMZb0cRKQctHNL4ceRZSsUUERA/s400/IMG_0449+%28Large%29.JPG" alt="" id="BLOGGER_PHOTO_ID_5353208597543766946" border="0" /></a>They looked otherworldly.<br /></div><br />Mammatus clouds are cumulus clouds characterized by the pouch-shaped formations hanging underneath. These clouds are associated with strong storms and can only exist when cumulonimbus clouds are also around.That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com1tag:blogger.com,1999:blog-30612507.post-33695978591259126312008-08-14T23:42:00.000-07:002008-08-15T10:52:56.873-07:00Caught A RainbowLuckily with the constant summer showers I was able to catch several rainbows. The one pictured below was the best of the bunch. It was just a simple rainbow no secondary arc.<br /><br /><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi5Icslt5z9yOQ2qsXA9wfa1x4GwjzcpTDNXqf50wat50_cOR8PhjSQ2kF_FRkzbdT0CV1vKISWbow8SHciloR2pWUhjrxw3DX2tUeUHZCvC4DDHMpPUI9koH285seSP7OWfHfUAw/s1600-h/IMG_5623.JPG"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 436px; height: 326px;" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi5Icslt5z9yOQ2qsXA9wfa1x4GwjzcpTDNXqf50wat50_cOR8PhjSQ2kF_FRkzbdT0CV1vKISWbow8SHciloR2pWUhjrxw3DX2tUeUHZCvC4DDHMpPUI9koH285seSP7OWfHfUAw/s400/IMG_5623.JPG" alt="" id="BLOGGER_PHOTO_ID_5234797485412961298" border="0" /></a><br />Straight from the fire escape at the end of the mini-storm. I learned the easiest way to find a rainbow is while it's raining wait for sun to come out and then turn your back to the sun.<br /><br /><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjjq4t8hShQYbwwcQfb41U3_R8Q7EkBvAh5Lb-uJHxr6ObzMRKbC4SBOCo6Z8a3PnsVORkU7n967B_u5-zneIDoDvXpj73ygCu4WympAqot3-YY1tnG9BT9v9Yygc7BsKgNSAcMEw/s1600-h/IMG_5624.JPG"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 436px; height: 328px;" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjjq4t8hShQYbwwcQfb41U3_R8Q7EkBvAh5Lb-uJHxr6ObzMRKbC4SBOCo6Z8a3PnsVORkU7n967B_u5-zneIDoDvXpj73ygCu4WympAqot3-YY1tnG9BT9v9Yygc7BsKgNSAcMEw/s400/IMG_5624.JPG" alt="" id="BLOGGER_PHOTO_ID_5234800464882288578" border="0" /></a><br />Sure the technical way to locate a rainbow is look for a multicolored arc at a 42° radius, with an option of a secondary inverse rainbow at 51° radius. The problem is that most people can't judge these exact degrees. Also trying to capture a secondary bow with a lower end digital camera is tough.<br /><br />As long as you have small water drops then the light entering it can refract and separate into the seven colors we see.That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-58426650783735808312008-07-14T22:40:00.000-07:002008-07-14T23:42:41.830-07:00Science In The SkyBesides the boring engineering stuff I have to do for college and the Excel sheets and all the MATLAB code I try and take scientific photos.<br /><br />I got the book National Audubon Society Field Guide to North American Weather and they have over 350 beautifully colored pages of different weather phenomena. My plan is to duplicate each photo subject through my window.<br /><br />First up is the Optical Phenomena.<br /><br /><div style="text-align: center;"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhUbMVkIZ9rN7XPGcd2U7_jEKWaKxjmbeAzS2wuMFXvlltTy0WsomCwqIOOh-svVjJHMr-fbJxE8lbDB5eQffwpsX09AYjK_GjcM23WP6fxNgT_cgXXxW7iYkvcs-vy2kSEL7C48g/s1600-h/IMG_4594.JPG"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 455px; height: 341px;" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhUbMVkIZ9rN7XPGcd2U7_jEKWaKxjmbeAzS2wuMFXvlltTy0WsomCwqIOOh-svVjJHMr-fbJxE8lbDB5eQffwpsX09AYjK_GjcM23WP6fxNgT_cgXXxW7iYkvcs-vy2kSEL7C48g/s400/IMG_4594.JPG" alt="" id="BLOGGER_PHOTO_ID_5223119942933975922" border="0" /></a>Can you guess what is pictured?<br /></div><br /><div style="text-align: center;"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiTBHgGWuJmBJeaT_wKlPB2MZd0jWl98SU4oRHYbL5WmEoa3KM_M3gm6VrYA_N6whqbF9eNTaNDWWUdxhJikP8ibs4fzfoV9Z8hRcNU7kAiBS76xStOnmWWZhPWSsdqCoM-_8UbnQ/s1600-h/IMG_4598.JPG"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 457px; height: 342px;" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiTBHgGWuJmBJeaT_wKlPB2MZd0jWl98SU4oRHYbL5WmEoa3KM_M3gm6VrYA_N6whqbF9eNTaNDWWUdxhJikP8ibs4fzfoV9Z8hRcNU7kAiBS76xStOnmWWZhPWSsdqCoM-_8UbnQ/s400/IMG_4598.JPG" alt="" id="BLOGGER_PHOTO_ID_5223120465961384370" border="0" /></a>A closer view may help.<br /></div><br /><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgg98EPOQQjRbMkFvYL239YEHpdK9Rr5lc2eyYg0nEFVpCyocK5HJ25Nsf-UtImwqP8pFJST64dSS4VwDaMsUlFfziKzuNX6S_xMQ7vMcezHW2Api6g1G1xrZroRQEPgrCMWwpCtw/s1600-h/IMG_4606.JPG"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 454px; height: 341px;" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgg98EPOQQjRbMkFvYL239YEHpdK9Rr5lc2eyYg0nEFVpCyocK5HJ25Nsf-UtImwqP8pFJST64dSS4VwDaMsUlFfziKzuNX6S_xMQ7vMcezHW2Api6g1G1xrZroRQEPgrCMWwpCtw/s400/IMG_4606.JPG" alt="" id="BLOGGER_PHOTO_ID_5223120986950108658" border="0" /></a><br /><div style="text-align: center;">Finally a broad shot.<br /></div><br />The first two pictures were of sun dogs and the last also has a halo.<br /><br />Sun dogs are known more formally as parhelia they often appear in pairs but in this case only one was visible. They can be solid white light or as seen more of a rainbow effect with the red closer to the sun and blue away from the sun. They are found to the right or left of the sun on the same plane and seen at a 22-24 degree distance.<br /><br />This one had an accompanying parhelic circle or halo. Haloes are formed when light gets refracted through ice crystals in cirriform clouds. The ice crystals must be hexagonal with two flat ends.<br /><br />Now this phenomina can occur all over the country and at any time of year but is most common in the southwest and before and after storms.<br /><br />Today's Links: <a href="http://www.atoptics.co.uk/">http://www.atoptics.co.uk/</a>That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-82032228789227292642008-04-08T21:46:00.000-07:002009-07-17T21:26:40.462-07:00Who knew?Engineering is a tough subject. <div style="margin-top: 10px; height: 15px;" class="zemanta-pixie"><br /><span class="zem-script more-related pretty-attribution"><script type="text/javascript" src="http://static.zemanta.com/readside/loader.js" defer="defer"></script></span></div>That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-24490823907743637642007-08-27T21:06:00.000-07:002009-07-17T21:27:19.365-07:00Chapter 11:Kinematics of pariclesDynamics: Deals with objects moving with an accelerated motion.<br /> It's concerned with the equilibrium of these objects.<br /><br />Kinematics: It relates position, displacement, velocity, acceleration, and time.<br /><br />Rectilinear motion of particles.<br /> A particle is in rectilinear if it is moving along a straight line.<br />*Position: Xp: position coordinate of the particle<br /> : algebraic scalar<br /> rp: position vector<br />*Displacement:That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-58594767640714670532007-08-02T13:42:00.000-07:002007-08-02T14:27:05.959-07:00Bridge Collapse<div style="text-align: right;"><div style="text-align: left;"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj4Mf2TWB46qb0jQ66-_h8ccaq5yIacmSEB_ktgip2-0XBPSNutFx6VnQiZ-zfu1YClsxtWODcLD4Zzqxwg_z3iYRlVfkEYAvldHBrJRSdJTWmGtkwhTt3CDYJSr-ptgGx4wvDGLg/s1600-h/410w.jpg"><img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 285px; height: 201px;" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj4Mf2TWB46qb0jQ66-_h8ccaq5yIacmSEB_ktgip2-0XBPSNutFx6VnQiZ-zfu1YClsxtWODcLD4Zzqxwg_z3iYRlVfkEYAvldHBrJRSdJTWmGtkwhTt3CDYJSr-ptgGx4wvDGLg/s400/410w.jpg" alt="" id="BLOGGER_PHOTO_ID_5094213140754488162" border="0" /></a>Just like the World Trade Center collapse the Minneapolis bridge collapse was probably do to a fatigue in the steel pins.<br /></div></div><br />The National Transportation Safety Board(NTSB) will use a special software developed by a local university to analyze the collapse. This is why learning programming is important. A individual invented the software that will analyze the disaster.<br /><br />I will start to update this blog with the tools I need to continue in engineering.<br /><br /><div style="text-align: right;">(AP Photo/Jacob Reynolds)<br /></div>That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-1154920639844840322006-08-06T20:17:00.000-07:002007-08-02T13:51:18.114-07:00Polyfitting in MATLABclc,clear<br />disp(<span style="color: rgb(204, 0, 0);">'Your Name'</span>)<br />t=[1,2,3,4,5,6];<br />y=[42,83,102,124,129,120];<br />coef=polyfit(t,y,2);<br />a1=coef(1);<br />a2=coef(2);<br />a3=coef(3);<br />disp(<span style="color: rgb(204, 0, 0);">'The values of g and vo are...'</span>)<br />g=-2*a1<br />vo=a2<br />yf=polyval(coef,t);<br />disp(<span style="color: rgb(204, 0, 0);">' time y fitting y'</span>)<br />disp(<span style="color: rgb(204, 0, 0);">' '</span>)<br />disp([t',y',yf'])<br />plot(t,y,<span style="color: rgb(204, 0, 0);">'o'</span>,t,yf)That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com1tag:blogger.com,1999:blog-30612507.post-1154839367590579472006-08-05T21:36:00.000-07:002007-08-02T13:52:39.861-07:00Rocket Trajectory for MATLAB 5.3<span style="color: rgb(51, 204, 0);"> %Problem #2 Chapter #3 page 121 rocket trajectory</span><br /><br />clc,clear<br /><br />disp(<span style="color: rgb(204, 0, 0);">'Your Name'</span>)<br />disp(<span style="color: rgb(204, 0, 0);">'-'</span>)<br />disp(<span style="color: rgb(204, 0, 0);">'-'</span>)<br /><br />t = 0:2:100;<br /><br /><span style="color: rgb(51, 51, 255);">for</span> n = 1:51;<br /> time = t(n);<br /><br /> h(n) = 60 + (2.13 * (time^2)) - (.0013 * (time^4)) + (.000034 * (time^4.751));<br /><span style="color: rgb(51, 51, 255);"> if</span> h(n) >= 0 | h(n) <=0 [d, dtime] = max(h); [i, impact] = min(h); <span style="color: rgb(51, 51, 255);"> end</span><br /><span style="color: rgb(51, 51, 255);"> end</span><br /><span style="color: rgb(51, 51, 255);"> end</span><br />disp(<span style="color: rgb(204, 0, 0);">'This is the time in seconds after which the rocket starts to fall.'</span>)<br />t(dtime)<br />t(impact);<br />n = 1:51;<br />time = t(n);<br />[h(n)',time'];<br /><br /><span style="color: rgb(51, 51, 255);">for</span> n = 1:51;<br /> time = t(n);<br /><br /> h(n) = 60 + (2.13 * (time^2)) - (.0013 * (time^4)) + (.000034 * (time^4.751));<br /><span style="color: rgb(51, 51, 255);"> if </span>h(n) <=0 disp(<span style="color: rgb(204, 0, 0);">'This is the time in seconds when the rocket has hit the ground.'</span>)<br /> time<br /><span style="color: rgb(51, 51, 255);">break</span><br /><span style="color: rgb(51, 51, 255);"> end</span><br /><span style="color: rgb(51, 51, 255);"> end</span>That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-1153607342174004262006-07-22T15:16:00.000-07:002007-08-02T13:52:59.014-07:00More Practice<span style="color: rgb(0, 153, 0);"> %Analytical theory</span><br />R1=1;<br />R2=2;<br />V1=12<br />Rth=R1+R2;<br />Ith=V1./Rth;<br />Vn1=Ith.*R1;<br />Vn2=Ith.*R2<br />V1=0:0.5:10<br />Ith=V1./Rth;<br />Vn1=Ith.*R1;<br />Vn2=Ith.*R2;<br />disp(<span style="color: rgb(204, 0, 0);">'Source volt Node Volt.'</span>)<br />Theory=[V1', Vn2']<br /><br /><br />subplot(2,2,1),plot(dcsweewb,Theory,<span style="color: rgb(204, 0, 0);">'*'</span>),title(<span style="color: rgb(204, 0, 0);">'Source vs. Node'</span>)<br />xlabel(<span style="color: rgb(204, 0, 0);">'Node voltage'</span>),ylabel(<span style="color: rgb(204, 0, 0);">'Source voltage'</span>)<br />subplot(2,2,2),plot(pasweewb,<span style="color: rgb(204, 0, 0);">'*'</span>),title(<span style="color: rgb(204, 0, 0);">'Parameter Sweep'</span>)<br />xlabel(<span style="color: rgb(204, 0, 0);">'Resistance in ohms'</span>),ylabel(<span style="color: rgb(204, 0, 0);">'Current in amps'</span>)<br />subplot(2,2,3),plot(transweb),title(<span style="color: rgb(204, 0, 0);">'Transient'</span>)<br />xlabel(<span style="color: rgb(204, 0, 0);">'Time in seconds'</span>),ylabel(<span style="color: rgb(204, 0, 0);">'Node voltage')</span><br />subplot(2,2,4),plot(project1),title(<span style="color: rgb(204, 0, 0);">'Labview'</span>)<br />xlabel(''),ylabel('')<br /><br />»<br />V1 =<br /><br /> 12<br /><br /><br />Vn2 =<br /><br /> 8<br /><br /><br />V1 =<br /><br />Columns 1 through 7<br /><br /> 0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000<br /><br />Columns 8 through 14<br /><br /> 3.5000 4.0000 4.5000 5.0000 5.5000 6.0000 6.5000<br /><br />Columns 15 through 21<br /><br /> 7.0000 7.5000 8.0000 8.5000 9.0000 9.5000 10.0000<br /><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://photos1.blogger.com/blogger/3681/495/1600/image002.gif"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer;" src="http://photos1.blogger.com/blogger/3681/495/320/image002.png" alt="" border="0" /></a>That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-1152686422600738952006-07-11T23:06:00.000-07:002007-08-02T13:53:24.321-07:00MATLAB 5.3: Two Age Programsclc <span style="color: rgb(0, 153, 0);">%For a SIMPLE solution</span><br />clear<br />age=input(<span style="color: rgb(204, 0, 0);">'Enter your age :'</span>)<br /><span style="color: rgb(51, 51, 255);">if</span> age > 65<br /> disp(<span style="color: rgb(204, 0, 0);">'senior'</span>)<br /><span style="color: rgb(51, 51, 255);">elseif</span> age > 20<br /> disp(<span style="color: rgb(204, 0, 0);">'adult'</span>)<br /><span style="color: rgb(51, 51, 255);"> elseif</span> age > 13<br /> disp(<span style="color: rgb(204, 0, 0);">'teen'</span>)<br /><span style="color: rgb(51, 51, 255);"> elseif</span> age > 0<br /> disp(<span style="color: rgb(204, 0, 0);">'child'</span>)<br /><span style="color: rgb(51, 51, 255);"> elseif</span> age < style="color: rgb(204, 0, 0);">'unborn'</span>)<br /><span style="color: rgb(51, 51, 255);"> end</span><br /><br /><br /><br />clc <span style="color: rgb(0, 153, 0);">%For a RANGE solution</span><br />clear<br />age=input(<span style="color: rgb(204, 0, 0);">'Enter your age :'</span>)<br /><span style="color: rgb(51, 51, 255);">if</span> age < style="color: rgb(204, 0, 0);">'unborn'</span>)<br /><span style="color: rgb(51, 51, 255);"> elseif</span> 0<=age & age <=12 disp(<span style="color: rgb(204, 0, 0);">'child')</span><br /><span style="color: rgb(51, 51, 255);"> elseif</span> 13<=age & age <=19 disp(<span style="color: rgb(204, 0, 0);">'teen'</span>)<br /><span style="color: rgb(51, 51, 255);"> elseif </span>20<=age & age <=65 disp(<span style="color: rgb(204, 0, 0);">'adult'</span>)<br /><span style="color: rgb(51, 51, 255);"> else</span><br /> disp(<span style="color: rgb(204, 0, 0);">'senior'</span>)<br /><span style="color: rgb(51, 51, 255);"> end<br /><br /><span style="color: rgb(0, 0, 0);">The homework solution was the second one but I came up with the first and it was accepted as the right answer.</span><br /></span>That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-1152225441444767472006-07-06T15:33:00.000-07:002007-08-02T13:53:53.697-07:00MATLAB 5.3: Data FilesThis homework will ask a user to enter 10 lottery numbers in two panels and then display those numbers in a table also a MS-WORD file will be brought in and display along with all variables used. The first will be saved as an ASCII/.dat file. <br /><br /><span style="color: rgb(51, 204, 0);"><br />%saving and loading files by Your Name Here</span><br /><br />clc<br />lotto1=input(<span style="color: rgb(204, 0, 0);">'Enter 5 numbers for the first lottery ticket panel'</span>);<br />lotto2=input(<span style="color: rgb(204, 0, 0);">'Enter 5 different numbers for the second lottery ticket panel'</span>);<br />disp(<span style="color: rgb(204, 0, 0);">'pick 1 pick 2'</span>)<br />table=[lotto1',lotto2'];<br />disp(table)<br />save yournamehere51.dat table /ascii<br />load YNHword.txt<br />disp(<span style="color: rgb(204, 0, 0);">'This is a MS Word file created earlier.'</span>)<br />disp(YNHword)<br />who<br />clear<br /><br /><strong>Enter 5 numbers for the first lottery ticket panel[1,2,3,4,5]<br />Enter 5 different numbers for the second lottery ticket panel[6,7,8,9,99]<br />pick 1 pick 2<br />1 6<br />2 7<br />3 8<br />4 9<br />5 99<br /><br />This is a MS Word file created earlier.<br />4 6 7<br />12 23 76<br /><br /><br />Your variables are:<br /><br />YNHword lotto1 lotto2 table</strong>That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-1151969401229125322006-07-03T16:29:00.000-07:002007-08-02T13:54:29.046-07:00MATLAB 5.3: PlottingWe were given three variables x, y1 and y2 and are asked to make two graphs and show procedures and results.<br /><br /><span style="color: rgb(51, 204, 0);">%two graphs are to be plotted along with rows and columns</span> <br />clc<br />disp(<span style="color: rgb(204, 0, 0);">'Your name here'</span>)<br />x=0:10;<br />y1=0:10:100;<br />y2=[0,1,4,9,16,25,36,49,64,81,100];<br />disp(y1);<br />disp([y1]');<br />firstcomp=y2(6);<br />disp(firstcomp)<br />subplot(2,1,1),plot(x,y1);<br />title(<span style="color: rgb(204, 0, 0);">'Homework #? Graph'</span>);<br />xlabel(<span style="color: rgb(204, 0, 0);">'X Values''Y1 Values'</span>);<br />subplot(2,1,2),plot(x,y1,x,y2,<span style="color: rgb(204, 0, 0);">'o'</span>);<br />title(<span style="color: rgb(204, 0, 0);">'Homework #? Graph'</span>);<br />xlabel(<span style="color: rgb(204, 0, 0);">'X Values'</span>),ylabel(<span style="color: rgb(204, 0, 0);">'Y2 Values'</span>)<br />Your name here<br />0 10 20 30 40 50 60 70 80 90 100<br /><br />0<br />10<br />20<br />30<br />40<br />50<br />60<br />70<br />80<br />90<br />100<br /><br />25That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-1151968828983306032006-07-03T16:12:00.000-07:002007-08-02T13:59:12.840-07:00Equilibrium Particles in Space<span style="font-weight: bold;"> Objective:</span> To determine the tension of cables both theoretically and experimentally. We will hang three cables at different locations on the ceiling of the force table. We will then tie about a 6kg mass to the end of the cables and measure the length of the cables. We will then calculate the tension using this information. Afterwards we will find the actual force using the spring scales at the top of the cable. The two answers will be compared and the percent error calculated. An explanation must be given for any percent difference.<br /><br /><br /><span style="font-weight: bold;">Equipment Needed: </span><br />- 3 Cables -3 Hooks<br />- Load -Meter stick<br />- 3 Scales -Force table<br /><br /><span style="font-weight: bold;">Experimental Procedure: </span>We get access to a force table and make sure it is up to working conditions. We then screw 3 hooks at 3 separate locations on the ceiling in the forces table, we then tighten them with nuts and washers. Then a spring scale is attached to each hook. Next cut a piece of string and tie one end to a hook. Do the preceding 2 more times for each hook and scale. Next tie all three strings together and place a 6.05kg mass on the point the strings meet. Then find a point on the ceiling that is perpendicular to the point where all the strings meet. This will be your zero point origin on the x, y, and z axes. Also find the distance from the origin on the ceiling to all three hooks along the x, y, and z axes. Then measure the distance of the string make sure to include the spring scale. Record all the measurements.<br /><br /><br /><span style="font-weight: bold;">Theory:</span> Equilibrium of particles in space is the theory that when the particle O is in equilibrium the sum of all forces is zero.<br /> Fx = 0 Fy = 0Fz = 0<br /><br /><br /><span style="font-weight: bold;">Results: </span>In centimeters and kilograms and Newton.<br /> A (-49, 73.5, 4.5) AO=87.5cm TOA = 24.5N<br /> B (-10, 73.5 -45.5) BO=87cm TOB =14.7N<br /> C (40, 73.5, 19) CO=86.5cm TOC =33.3N O (0, 0, 0) W=6.05kg<br />Theoretical Calculations: Only using x, y, and z position not the cable lengths or<br /> tension found in experiment.<br /> <br /> I. W= -6.05kg (9.8m/s2) = -59.35N<br /> <br /> II. = A-O = (-49cm) î + (73.5cm) ĵ+ (4.5cm) k<br /> ____________________ <br /> OA=√ (-49)2+ (73.5)2+ (4.5) 2 = 88.45cm<br /><br /> λ OA = = -.55 î +.83 ĵ +.05 k<br /> 88.45<br /><br /> TOA λOA = -.55 TOA î +.83TOA ĵ +.05TOA k<br /><br /> III. =B-O = (-10cm) î + (73.5cm) ĵ + (-45.5cm) k<br /> ______________________<br /> OB=√ (-10) 2 + (73.5) 2 + (-45.5) 2 = 87.02cm<br /><br /> λ OB = = -.11 î +.84 ĵ -.52 k<br /> 87.02<br /><br /> TOB λOB = -.11 TOB î +.84TOB ĵ +.52TOB k<br /><br /> IV.OC = C-O = (40cm) î + (73.5cm) ĵ + (19cm) k<br /> __________________<br /> OC=√ (40) 2+ (73.5) 2+ (19) 2 =85.81cm<br /><br /> λ OC = OC= -.47 î +.86 ĵ +.22 k<br /> 85.81<br /> TOC λOC = -.47 TOC î +.86TOC ĵ +.22TOC k<br /><br /> V. ∑Fx = 0<br /> -.55 TOA î -.11 TOB î -.47 TOC î = 0<br /> ∑Fy = 0<br /> 83TOA ĵ +.84TOB ĵ +.86TOC ĵ – 59.35N = 0<br /> ∑Fz = 0<br /> .05TOA k+.52TOB k+.22TOC k = 0<br /><br /><br /> VI. Solve for the three unknowns with the three equations with these results:<br /> <br /> TOA = 22.6N TOB = 15.4N TOC = 31.3N<br /><br /><br /><br /><br /><br />Percent Error: E = theoretical value (estimated)<br /> A = measured value (actual)<br /> | E – A | × 100<br /> A<br />Since I only used the position in space to calculate the cables tension and length I will have to find the percent error for OA, OB, OC, TOA, TOB and TOC.<br /><br /> OAE = 88.45 OBE = 87.02 OCE = 85.81<br /> OAA = 87.50 OBA = 87.00 OCA = 86.50<br />Percent error = 1.09% = 0.02% = 0.80%<br /><br /> TOA E = 22.6N TOB E = 15.4N TOC E = 31.3N<br /> TOA A = 24.5N TOB A = 14.7N TOC A = 33.3N<br />Percent error = 7.76% = 4.76% = 6.01%<br /><br /><br /><span style="font-weight: bold;">Conclusion:</span> The most likely reason for the error in the cable lengths is imprecise measurements by the people who did the measurements. When the meter stick was placed and the line plotted a small missed reading was put down. This gave the small percent errors for the lengths. This lead to a larger error when the figures were used in the more complicated tension formulas. The percent errors in tension then became much more magnified.<br /><br /><span style="font-weight: bold;">Repeat the experiment with out OB:</span><br /><span style="font-weight: bold;"> Given:</span> A (-48, 74.5, -5.8) W = 6.05kg <br /> C (41.5, 74.5, 6) TOA = 32.34N TOB = 35.28N<br /><br /> <br /><span style="font-weight: bold;"> Theoretical Calculations: </span>Only using x, y, and z position not the cable lengths or<br /> tension found in experiment.<br /><br /><br />1. = A-O = (-48cm) î + (74.5cm) ĵ+ (-5.8cm) k<br /> ____________________ <br /> OA=√ (-48)2+ (74.5)2+ (-5.8) 2 = 88.81cm<br /><br /> λ OA = = -.54 î +.84 ĵ -.07 k<br /> 88.81<br /><br /> TOA λOA = -.54 TOA î +.84TOA ĵ +.07TOA k<br /><br /><br /><br /><br /><br />2. OC =C-O = (-41.5cm) î + (74.5cm) ĵ + (6cm) k<br /> ______________________<br /> OC=√ (-41.5) 2 + (74.5) 2 + (6) 2 = 85.49cm<br /><br /> λ OC = OC= -.49 î +.87 ĵ -.07 k<br /> 85.49<br /><br /> TOB λOB = -.49 TOB î +.87TOB ĵ +.07TOB k<br /><br />3. ∑Fx = 0<br /> -.54 TOA î-.49 TOB î = 0<br /> ∑Fy = 0<br /> .84TOA ĵ+.87TOB ĵ -59.35N= 0<br /> ∑Fz = 0<br /> .07TOA k+.07TOB k = 0<br /><br />4. Solve for the two unknowns with the three equations with these results:<br /><br /> TOA = 32.99N TOB = 36.36N<br /><br />5. <span style="font-weight: bold;">Percent Error:</span> E = theoretical value (estimated)<br /> A = measured value (actual)<br /> | E – A | × 100<br /> A<br /><br /> OAE = 88.81 OCE = 85.49 <br /> OAA = 87.50 OCA = 86.50 <br />Percent error = 1.50% =1.16% <br /><br /> TOA E = 32.99N TOC E = 36.36N <br /> TOA A = 32.34N TOC A = 35.28N <br />Percent error = 2.01% =3.06 %<br /><br /><span style="font-weight: bold;">Conclusion:</span> The tension on the cables increased as expected with the removal of cable OB. The percent error was closer to the actual measurements mostly because there were fewer things to plot.That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0tag:blogger.com,1999:blog-30612507.post-1151966085161179802006-07-03T15:27:00.000-07:002009-07-17T21:27:44.686-07:00Engineering School HomeworkThis is going to a place where I can store my old engineering work from college.<br /><br />It includes MATLAB programs, Microsoft Excel, AutoCAD, Electronics Workbench and any others I use but now forgot.<br /><br />It is a shame that blogger doesn't have catagories but I'll just use the search tool.<br /><br />As for me well I don't matter just the fact that I'm trying to pass my classes and may need some input.That Other Manhttp://www.blogger.com/profile/16429533907522289041noreply@blogger.com0